Introduction

In this blog post, we will explore how to solve the LeetCode problem "3349" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an array nums of n integers and an integer k, determine whether there exist two adjacent subarrays of length k such that both subarrays are strictly increasing. Specifically, check if there are two subarrays starting at indices a and b (a < b), where: Both subarrays nums[a..a + k - 1] and nums[b..b + k - 1] are strictly increasing. The subarrays must be adjacent, meaning b = a + k. Return true if it is possible to find two such subarrays, and false otherwise. Example 1: Input: nums = [2,5,7,8,9,2,3,4,3,1], k = 3 Output: true Explanation: The subarray starting at index 2 is [7, 8, 9], which is strictly increasing. The subarray starting at index 5 is [2, 3, 4], which is also strictly increasing. These two subarrays are adjacent, so the result is true. Example 2: Input: nums = [1,2,3,4,4,4,4,5,6,7], k = 5 Output: false Constraints: 2 <= nums.length <= 100 1 < 2 * k <= nums.length -1000 <= nums[i] <= 1000

Explanation

Here's the solution:

• High-Level Approach: Iterate through the array, checking for strictly increasing subarrays of length k at each possible starting index. If an increasing subarray is found, check if the adjacent subarray (starting k positions later) is also strictly increasing. Return true immediately if both conditions are met.
• Complexity: O(n) time complexity, O(1) space complexity.

Code

    def check_adjacent_increasing_subarrays(nums, k):
    """
    Checks if there exist two adjacent subarrays of length k such that both subarrays are strictly increasing.

    Args:
        nums: A list of integers.
        k: The length of the subarrays.

    Returns:
        True if it is possible to find two such subarrays, and False otherwise.
    """

    n = len(nums)

    def is_strictly_increasing(arr):
        """Helper function to check if a subarray is strictly increasing."""
        for i in range(len(arr) - 1):
            if arr[i] >= arr[i + 1]:
                return False
        return True

    for i in range(n - 2 * k + 1):
        subarray1 = nums[i:i + k]
        subarray2 = nums[i + k:i + 2 * k]

        if is_strictly_increasing(subarray1) and is_strictly_increasing(subarray2):
            return True

    return False