# Solving Leetcode Interviews in Seconds with AI: Angle Between Hands of a Clock


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1344" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given two numbers, hour and minutes, return the smaller angle (in degrees) formed between the hour and the minute hand. Answers within 10-5 of the actual value will be accepted as correct.   Example 1:   Input: hour = 12, minutes = 30 Output: 165  Example 2:   Input: hour = 3, minutes = 30 Output: 75  Example 3:   Input: hour = 3, minutes = 15 Output: 7.5    Constraints:  1 <= hour <= 12 0 <= minutes <= 59  

	# Explanation
	Here's an efficient solution to calculate the smaller angle between the hour and minute hands:

*   **Calculate Angles:** Determine the angles of the hour and minute hands relative to the 12 o'clock position.
*   **Find Difference:** Calculate the absolute difference between the two angles.
*   **Minimize Angle:** Ensure the returned angle is the smaller of the two possible angles (<= 180 degrees).

*   **Runtime Complexity:** O(1), **Storage Complexity:** O(1)

	
	# Code
	```python
	def angleClock(hour: int, minutes: int) -> float:
    """
    Calculates the smaller angle between the hour and minute hands of a clock.

    Args:
        hour: The hour (1-12).
        minutes: The minutes (0-59).

    Returns:
        The smaller angle in degrees between the hour and minute hands.
    """

    # Calculate the angle of the minute hand
    minute_angle = minutes * 6  # 360 degrees / 60 minutes = 6 degrees/minute

    # Calculate the angle of the hour hand
    # Each hour is 30 degrees (360 / 12)
    # Plus, the hour hand moves a fraction of 30 degrees based on the minutes
    hour_angle = (hour % 12 + minutes / 60) * 30

    # Calculate the absolute difference between the two angles
    angle_difference = abs(hour_angle - minute_angle)

    # Return the smaller angle
    return min(angle_difference, 360 - angle_difference)
	```