Introduction

In this blog post, we will explore how to solve the LeetCode problem "561" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an integer array nums of 2n integers, group these integers into n pairs (a1, b1), (a2, b2), ..., (an, bn) such that the sum of min(ai, bi) for all i is maximized. Return the maximized sum. Example 1: Input: nums = [1,4,3,2] Output: 4 Explanation: All possible pairings (ignoring the ordering of elements) are: 1. (1, 4), (2, 3) -> min(1, 4) + min(2, 3) = 1 + 2 = 3 2. (1, 3), (2, 4) -> min(1, 3) + min(2, 4) = 1 + 2 = 3 3. (1, 2), (3, 4) -> min(1, 2) + min(3, 4) = 1 + 3 = 4 So the maximum possible sum is 4. Example 2: Input: nums = [6,2,6,5,1,2] Output: 9 Explanation: The optimal pairing is (2, 1), (2, 5), (6, 6). min(2, 1) + min(2, 5) + min(6, 6) = 1 + 2 + 6 = 9. Constraints: 1 <= n <= 104 nums.length == 2 * n -104 <= nums[i] <= 104

Explanation

Here's the solution to the problem:

• Sorting: Sort the input array nums in ascending order.
• Pairing: Iterate through the sorted array, taking pairs of adjacent elements.

• Summation: Sum the minimum value of each pair. Because the array is sorted, the minimum value of each pair will always be the first element of the pair.

• Runtime Complexity: O(n log n) due to sorting. Storage Complexity: O(1) or O(n), depending on the sorting algorithm's space complexity (in-place sorting algorithms can achieve O(1), while others might use O(n)).

Code

    def array_pair_sum(nums):
    """
    Given an integer array nums of 2n integers, group these integers into n pairs (a1, b1), (a2, b2), ..., (an, bn)
    such that the sum of min(ai, bi) for all i is maximized. Return the maximized sum.

    Args:
    nums (List[int]): An array of integers.

    Returns:
    int: The maximized sum of the minimum values in each pair.
    """
    nums.sort()
    max_sum = 0
    for i in range(0, len(nums), 2):
        max_sum += nums[i]
    return max_sum