Introduction

In this blog post, we will explore how to solve the LeetCode problem "2455" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an integer array nums of positive integers, return the average value of all even integers that are divisible by 3. Note that the average of n elements is the sum of the n elements divided by n and rounded down to the nearest integer. Example 1: Input: nums = [1,3,6,10,12,15] Output: 9 Explanation: 6 and 12 are even numbers that are divisible by 3. (6 + 12) / 2 = 9. Example 2: Input: nums = [1,2,4,7,10] Output: 0 Explanation: There is no single number that satisfies the requirement, so return 0. Constraints: 1 <= nums.length <= 1000 1 <= nums[i] <= 1000

Explanation

• Iterate through the input array nums.
  • Check each number if it is even and divisible by 3. If so, add it to the sum and increment the count.
  • After iterating through the entire array, calculate the average by dividing the sum by the count and truncating the decimal part. Return 0 if count is zero.

• Runtime complexity: O(n), Storage complexity: O(1)

Code

    def averageValue(nums):
    """
    Given an integer array nums of positive integers, return the average value of all even integers that are divisible by 3.

    Args:
        nums (List[int]): An array of positive integers.

    Returns:
        int: The average value of all even integers that are divisible by 3.
    """
    sum_val = 0
    count = 0
    for num in nums:
        if num % 2 == 0 and num % 3 == 0:
            sum_val += num
            count += 1
    if count == 0:
        return 0
    else:
        return sum_val // count