# Solving Leetcode Interviews in Seconds with AI: Average Value of Even Numbers That Are Divisible by Three


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "2455" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given an integer array nums of positive integers, return the average value of all even integers that are divisible by 3. Note that the average of n elements is the sum of the n elements divided by n and rounded down to the nearest integer.   Example 1:  Input: nums = [1,3,6,10,12,15] Output: 9 Explanation: 6 and 12 are even numbers that are divisible by 3. (6 + 12) / 2 = 9.  Example 2:  Input: nums = [1,2,4,7,10] Output: 0 Explanation: There is no single number that satisfies the requirement, so return 0.    Constraints:  1 <= nums.length <= 1000 1 <= nums[i] <= 1000  

	# Explanation
	*   Iterate through the input array `nums`.
*   Check each number if it is even and divisible by 3. If so, add it to the sum and increment the count.
*   After iterating through the entire array, calculate the average by dividing the sum by the count and truncating the decimal part. Return 0 if count is zero.

*   Runtime complexity: O(n), Storage complexity: O(1)

	
	# Code
	```python
	def averageValue(nums):
    """
    Given an integer array nums of positive integers, return the average value of all even integers that are divisible by 3.

    Args:
        nums (List[int]): An array of positive integers.

    Returns:
        int: The average value of all even integers that are divisible by 3.
    """
    sum_val = 0
    count = 0
    for num in nums:
        if num % 2 == 0 and num % 3 == 0:
            sum_val += num
            count += 1
    if count == 0:
        return 0
    else:
        return sum_val // count
	```