Introduction

In this blog post, we will explore how to solve the LeetCode problem "2706" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given an integer array prices representing the prices of various chocolates in a store. You are also given a single integer money, which represents your initial amount of money. You must buy exactly two chocolates in such a way that you still have some non-negative leftover money. You would like to minimize the sum of the prices of the two chocolates you buy. Return the amount of money you will have leftover after buying the two chocolates. If there is no way for you to buy two chocolates without ending up in debt, return money. Note that the leftover must be non-negative. Example 1: Input: prices = [1,2,2], money = 3 Output: 0 Explanation: Purchase the chocolates priced at 1 and 2 units respectively. You will have 3 - 3 = 0 units of money afterwards. Thus, we return 0. Example 2: Input: prices = [3,2,3], money = 3 Output: 3 Explanation: You cannot buy 2 chocolates without going in debt, so we return 3. Constraints: 2 <= prices.length <= 50 1 <= prices[i] <= 100 1 <= money <= 100

Explanation

Here's the breakdown of the solution:

• Sort the prices: Sorting allows us to efficiently find the two smallest prices using the first two elements.
• Check if affordable: We check if the sum of the two smallest prices is less than or equal to the given money.

• Return leftover or original amount: If affordable, return the leftover money; otherwise, return the original money.

• Runtime Complexity: O(n log n) due to sorting, where n is the number of prices. Storage Complexity: O(1) - constant extra space.

Code

    def buy_chocolates(prices, money):
    """
    Calculates the leftover money after buying two chocolates with the minimum cost.

    Args:
        prices (list of int): An integer array representing the prices of chocolates.
        money (int): The initial amount of money.

    Returns:
        int: The leftover money after buying two chocolates, or the original money if it's not possible to buy two chocolates.
    """
    prices.sort()
    if len(prices) < 2 or prices[0] + prices[1] > money:
        return money
    else:
        return money - (prices[0] + prices[1])