Introduction

In this blog post, we will explore how to solve the LeetCode problem "1023" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an array of strings queries and a string pattern, return a boolean array answer where answer[i] is true if queries[i] matches pattern, and false otherwise. A query word queries[i] matches pattern if you can insert lowercase English letters into the pattern so that it equals the query. You may insert a character at any position in pattern or you may choose not to insert any characters at all. Example 1: Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FB" Output: [true,false,true,true,false] Explanation: "FooBar" can be generated like this "F" + "oo" + "B" + "ar". "FootBall" can be generated like this "F" + "oot" + "B" + "all". "FrameBuffer" can be generated like this "F" + "rame" + "B" + "uffer". Example 2: Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBa" Output: [true,false,true,false,false] Explanation: "FooBar" can be generated like this "Fo" + "o" + "Ba" + "r". "FootBall" can be generated like this "Fo" + "ot" + "Ba" + "ll". Example 3: Input: queries = ["FooBar","FooBarTest","FootBall","FrameBuffer","ForceFeedBack"], pattern = "FoBaT" Output: [false,true,false,false,false] Explanation: "FooBarTest" can be generated like this "Fo" + "o" + "Ba" + "r" + "T" + "est". Constraints: 1 <= pattern.length, queries.length <= 100 1 <= queries[i].length <= 100 queries[i] and pattern consist of English letters.

Explanation

Here's a solution to the problem, including a high-level approach, complexity analysis, and the Python code.

• Iterate through queries: For each query string, check if it matches the pattern.
• Two Pointers Matching: Use two pointers, one for the query string and one for the pattern, to efficiently determine if the query can be generated from the pattern by inserting lowercase letters. Ensure that all uppercase letters in the query match the pattern.

• Validate Lowercase: Ensure that only lowercase letters are inserted. If an uppercase letter appears in the query that doesn't match the pattern, it's a mismatch.

• Runtime Complexity: O(m*n), where 'm' is the number of queries and 'n' is the maximum length of a query.

• Storage Complexity: O(m), where 'm' is the number of queries to store the boolean results.

Code

    def camelMatch(queries, pattern):
    """
    Checks if each query string matches the given pattern based on the problem description.

    Args:
        queries (list of str): A list of query strings.
        pattern (str): The pattern string.

    Returns:
        list of bool: A list of booleans indicating whether each query matches the pattern.
    """

    result = []
    for query in queries:
        result.append(is_match(query, pattern))
    return result

def is_match(query, pattern):
    """
    Checks if a single query string matches the given pattern.

    Args:
        query (str): The query string.
        pattern (str): The pattern string.

    Returns:
        bool: True if the query matches the pattern, False otherwise.
    """
    i, j = 0, 0
    while i < len(query):
        if j < len(pattern) and query[i] == pattern[j]:
            i += 1
            j += 1
        elif 'a' <= query[i] <= 'z':
            i += 1
        elif 'A' <= query[i] <= 'Z':
            return False
        else:
            return False

    return j == len(pattern)