Introduction

In this blog post, we will explore how to solve the LeetCode problem "605" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You have a long flowerbed in which some of the plots are planted, and some are not. However, flowers cannot be planted in adjacent plots. Given an integer array flowerbed containing 0's and 1's, where 0 means empty and 1 means not empty, and an integer n, return true if n new flowers can be planted in the flowerbed without violating the no-adjacent-flowers rule and false otherwise. Example 1: Input: flowerbed = [1,0,0,0,1], n = 1 Output: true Example 2: Input: flowerbed = [1,0,0,0,1], n = 2 Output: false Constraints: 1 <= flowerbed.length <= 2 * 104 flowerbed[i] is 0 or 1. There are no two adjacent flowers in flowerbed. 0 <= n <= flowerbed.length

Explanation

Here's a solution to the flower planting problem, designed for optimal efficiency:

• Greedy Planting: Iterate through the flowerbed, planting a flower whenever a plot and its adjacent plots are empty.

• Count and Compare: Keep track of the number of flowers planted. Return True if the number of planted flowers is greater than or equal to n, and False otherwise.

• Time Complexity: O(N), where N is the length of the flowerbed. Space Complexity: O(1).

Code

    def canPlaceFlowers(flowerbed, n):
    """
    Determines if n new flowers can be planted in the flowerbed without violating the no-adjacent-flowers rule.

    Args:
        flowerbed: An integer array containing 0's and 1's, where 0 means empty and 1 means not empty.
        n: The number of new flowers to plant.

    Returns:
        True if n new flowers can be planted, False otherwise.
    """

    count = 0
    length = len(flowerbed)
    for i in range(length):
        if flowerbed[i] == 0:
            empty_left = (i == 0) or (flowerbed[i - 1] == 0)
            empty_right = (i == length - 1) or (flowerbed[i + 1] == 0)

            if empty_left and empty_right:
                flowerbed[i] = 1  # Plant a flower
                count += 1
                if count >= n:
                    return True

    return count >= n