Introduction

In this blog post, we will explore how to solve the LeetCode problem "2525" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given four integers length, width, height, and mass, representing the dimensions and mass of a box, respectively, return a string representing the category of the box. The box is "Bulky" if: Any of the dimensions of the box is greater or equal to 104. Or, the volume of the box is greater or equal to 109. If the mass of the box is greater or equal to 100, it is "Heavy". If the box is both "Bulky" and "Heavy", then its category is "Both". If the box is neither "Bulky" nor "Heavy", then its category is "Neither". If the box is "Bulky" but not "Heavy", then its category is "Bulky". If the box is "Heavy" but not "Bulky", then its category is "Heavy". Note that the volume of the box is the product of its length, width and height. Example 1: Input: length = 1000, width = 35, height = 700, mass = 300 Output: "Heavy" Explanation: None of the dimensions of the box is greater or equal to 104. Its volume = 24500000 <= 109. So it cannot be categorized as "Bulky". However mass >= 100, so the box is "Heavy". Since the box is not "Bulky" but "Heavy", we return "Heavy". Example 2: Input: length = 200, width = 50, height = 800, mass = 50 Output: "Neither" Explanation: None of the dimensions of the box is greater or equal to 104. Its volume = 8 * 106 <= 109. So it cannot be categorized as "Bulky". Its mass is also less than 100, so it cannot be categorized as "Heavy" either. Since its neither of the two above categories, we return "Neither". Constraints: 1 <= length, width, height <= 105 1 <= mass <= 103

Explanation

• Calculate if the box is bulky by checking if any dimension is greater than or equal to 10⁴ or if the volume is greater than or equal to 10⁹.
  • Calculate if the box is heavy by checking if the mass is greater than or equal to 100.
  • Return the appropriate category string based on whether the box is bulky, heavy, both, or neither.

• Runtime Complexity: O(1), Storage Complexity: O(1)

Code

    def categorize_box(length: int, width: int, height: int, mass: int) -> str:
    """
    Given four integers length, width, height, and mass, representing the dimensions and mass of a box,
    respectively, return a string representing the category of the box.

    The box is "Bulky" if:
        Any of the dimensions of the box is greater or equal to 10^4.
        Or, the volume of the box is greater or equal to 10^9.

    If the mass of the box is greater or equal to 100, it is "Heavy".

    If the box is both "Bulky" and "Heavy", then its category is "Both".
    If the box is neither "Bulky" nor "Heavy", then its category is "Neither".
    If the box is "Bulky" but not "Heavy", then its category is "Bulky".
    If the box is "Heavy" but not "Bulky", then its category is "Heavy".

    Note that the volume of the box is the product of its length, width and height.
    """

    bulky = False
    heavy = False

    if length >= 10000 or width >= 10000 or height >= 10000 or length * width * height >= 1000000000:
        bulky = True

    if mass >= 100:
        heavy = True

    if bulky and heavy:
        return "Both"
    elif not bulky and not heavy:
        return "Neither"
    elif bulky:
        return "Bulky"
    else:
        return "Heavy"