# Solving Leetcode Interviews in Seconds with AI: Check If Two String Arrays are Equivalent


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1662" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given two string arrays word1 and word2, return true if the two arrays represent the same string, and false otherwise. A string is represented by an array if the array elements concatenated in order forms the string.   Example 1:  Input: word1 = ["ab", "c"], word2 = ["a", "bc"] Output: true Explanation: word1 represents string "ab" + "c" -> "abc" word2 represents string "a" + "bc" -> "abc" The strings are the same, so return true. Example 2:  Input: word1 = ["a", "cb"], word2 = ["ab", "c"] Output: false  Example 3:  Input: word1  = ["abc", "d", "defg"], word2 = ["abcddefg"] Output: true    Constraints:  1 <= word1.length, word2.length <= 103 1 <= word1[i].length, word2[i].length <= 103 1 <= sum(word1[i].length), sum(word2[i].length) <= 103 word1[i] and word2[i] consist of lowercase letters.  

	# Explanation
	Here's the breakdown of the solution:

*   **Two Pointers:** Use two pointers to iterate through the strings represented by `word1` and `word2` simultaneously. One pointer tracks the current word in `word1`, and another tracks the current word in `word2`. Inside each word, we use character index pointers to compare character by character.
*   **Character-by-Character Comparison:** Compare characters at the pointer locations in the two strings. If the characters don't match, return `False`.
*   **Pointer Updates:** Increment the character pointers and, if necessary, move to the next word in the array.

*   **Time Complexity:** O(N), where N is the total number of characters in both arrays. **Space Complexity:** O(1).

	
	# Code
	```python
	def arrayStringsAreEqual(word1: list[str], word2: list[str]) -> bool:
    """
    Given two string arrays word1 and word2, return true if the two arrays represent the same string, and false otherwise.
    A string is represented by an array if the array elements concatenated in order forms the string.
    """
    word1_idx = 0
    word2_idx = 0
    char1_idx = 0
    char2_idx = 0

    while word1_idx < len(word1) and word2_idx < len(word2):
        if word1[word1_idx][char1_idx] != word2[word2_idx][char2_idx]:
            return False

        char1_idx += 1
        if char1_idx == len(word1[word1_idx]):
            word1_idx += 1
            char1_idx = 0

        char2_idx += 1
        if char2_idx == len(word2[word2_idx]):
            word2_idx += 1
            char2_idx = 0

    return word1_idx == len(word1) and word2_idx == len(word2)
	```