Solving Leetcode Interviews in Seconds with AI: Convert to Base -2
Introduction
In this blog post, we will explore how to solve the LeetCode problem "1017" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
Given an integer n, return a binary string representing its representation in base -2. Note that the returned string should not have leading zeros unless the string is "0". Example 1: Input: n = 2 Output: "110" Explantion: (-2)2 + (-2)1 = 2 Example 2: Input: n = 3 Output: "111" Explantion: (-2)2 + (-2)1 + (-2)0 = 3 Example 3: Input: n = 4 Output: "100" Explantion: (-2)2 = 4 Constraints: 0 <= n <= 109
Explanation
Here's the breakdown of the solution:
- Iterative Conversion: Repeatedly apply modulo and division operations, similar to base-2 conversion, but using -2 as the base.
- Handling Negative Remainders: When the remainder is negative, adjust it to be positive by adding the absolute value of the base (2 in this case) and compensating by adding 1 to the quotient. This ensures correct handling in the negative base.
Building the String: Prepend the remainders (which are always 0 or 1 after the adjustments) to a string to build the base -2 representation.
Runtime Complexity: O(log n) & Storage Complexity: O(log n) - where n is the input integer.
Code
def baseNeg2(n: int) -> str:
"""
Converts an integer to its base -2 representation as a string.
Args:
n: The integer to convert.
Returns:
The base -2 representation of n as a string.
"""
if n == 0:
return "0"
result = ""
while n != 0:
remainder = n % -2
n //= -2
if remainder < 0:
remainder += 2
n += 1
result = str(remainder) + result
return result