# Solving Leetcode Interviews in Seconds with AI: Count Odd Numbers in an Interval Range


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1523" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given two non-negative integers low and high. Return the count of odd numbers between low and high (inclusive).   Example 1: 
 Input: low = 3, high = 7
 Output: 3
 Explanation: The odd numbers between 3 and 7 are [3,5,7]. Example 2: 
 Input: low = 8, high = 10
 Output: 1
 Explanation: The odd numbers between 8 and 10 are [9].   Constraints:  0 <= low <= high <= 10^9 

	# Explanation
	Here's an efficient solution to count odd numbers within a given range:

*   **Direct Calculation:** Instead of iterating through the range, we can directly calculate the number of odd numbers using integer division and considering whether the boundaries are odd or even.

*   **Handle Edge Cases:** Special attention is paid to the inclusive nature of the range and whether `low` and `high` are odd or even to ensure correct calculation.

*   **Optimization:** Avoid loops or recursion.  The logic leverages constant-time arithmetic operations.

*   **Runtime & Storage Complexity:** O(1) runtime and O(1) storage.

	
	# Code
	```python
	def count_odds(low: int, high: int) -> int:
    """
    Counts the number of odd numbers between low and high (inclusive).

    Args:
        low: The lower bound (inclusive).
        high: The upper bound (inclusive).

    Returns:
        The number of odd numbers in the range.
    """
    n = (high - low) // 2
    if low % 2 != 0 or high % 2 != 0:
        n += 1
    return n
	```