Solving Leetcode Interviews in Seconds with AI: Count Pairs That Form a Complete Day I
Introduction
In this blog post, we will explore how to solve the LeetCode problem "3184" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
Given an integer array hours representing times in hours, return an integer denoting the number of pairs i, j where i < j and hours[i] + hours[j] forms a complete day. A complete day is defined as a time duration that is an exact multiple of 24 hours. For example, 1 day is 24 hours, 2 days is 48 hours, 3 days is 72 hours, and so on. Example 1: Input: hours = [12,12,30,24,24] Output: 2 Explanation: The pairs of indices that form a complete day are (0, 1) and (3, 4). Example 2: Input: hours = [72,48,24,3] Output: 3 Explanation: The pairs of indices that form a complete day are (0, 1), (0, 2), and (1, 2). Constraints: 1 <= hours.length <= 100 1 <= hours[i] <= 109
Explanation
Here's the breakdown:
High-Level Approach:
- Iterate through the array. For each element
hours[i], check elementshours[j]wherej > i. - Determine if the sum
hours[i] + hours[j]is divisible by 24. - Increment a counter if the sum is divisible by 24.
- Iterate through the array. For each element
Complexity:
- Runtime: O(n^2), Storage: O(1)
Code
def complete_days(hours):
"""
Calculates the number of pairs (i, j) where i < j and hours[i] + hours[j] is a multiple of 24.
Args:
hours: A list of integers representing hours.
Returns:
An integer representing the number of pairs that form a complete day.
"""
count = 0
n = len(hours)
for i in range(n):
for j in range(i + 1, n):
if (hours[i] + hours[j]) % 24 == 0:
count += 1
return count