# Solving Leetcode Interviews in Seconds with AI: Count Pairs That Form a Complete Day I


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "3184" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given an integer array hours representing times in hours, return an integer denoting the number of pairs i, j where i < j and hours[i] + hours[j] forms a complete day. A complete day is defined as a time duration that is an exact multiple of 24 hours. For example, 1 day is 24 hours, 2 days is 48 hours, 3 days is 72 hours, and so on.   Example 1:  Input: hours = [12,12,30,24,24] Output: 2 Explanation: The pairs of indices that form a complete day are (0, 1) and (3, 4).  Example 2:  Input: hours = [72,48,24,3] Output: 3 Explanation: The pairs of indices that form a complete day are (0, 1), (0, 2), and (1, 2).    Constraints:  1 <= hours.length <= 100 1 <= hours[i] <= 109  

	# Explanation
	Here's the breakdown:

*   **High-Level Approach:**
    *   Iterate through the array. For each element `hours[i]`, check elements `hours[j]` where `j > i`.
    *   Determine if the sum `hours[i] + hours[j]` is divisible by 24.
    *   Increment a counter if the sum is divisible by 24.

*   **Complexity:**
    *   Runtime: O(n^2), Storage: O(1)

	
	# Code
	```python
	def complete_days(hours):
    """
    Calculates the number of pairs (i, j) where i < j and hours[i] + hours[j] is a multiple of 24.

    Args:
        hours: A list of integers representing hours.

    Returns:
        An integer representing the number of pairs that form a complete day.
    """

    count = 0
    n = len(hours)

    for i in range(n):
        for j in range(i + 1, n):
            if (hours[i] + hours[j]) % 24 == 0:
                count += 1

    return count
	```