Introduction

In this blog post, we will explore how to solve the LeetCode problem "1267" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given a map of a server center, represented as a m * n integer matrix grid, where 1 means that on that cell there is a server and 0 means that it is no server. Two servers are said to communicate if they are on the same row or on the same column. Return the number of servers that communicate with any other server. Example 1: Input: grid = [[1,0],[0,1]] Output: 0 Explanation: No servers can communicate with others. Example 2: Input: grid = [[1,0],[1,1]] Output: 3 Explanation: All three servers can communicate with at least one other server. Example 3: Input: grid = [[1,1,0,0],[0,0,1,0],[0,0,1,0],[0,0,0,1]] Output: 4 Explanation: The two servers in the first row can communicate with each other. The two servers in the third column can communicate with each other. The server at right bottom corner can't communicate with any other server. Constraints: m == grid.length n == grid[i].length 1 <= m <= 250 1 <= n <= 250 grid[i][j] == 0 or 1

Explanation

Here's the breakdown of the solution:

• Count Servers per Row/Column: Iterate through the grid to count the number of servers in each row and each column.
• Identify Communicating Servers: Iterate through the grid again. A server at grid[i][j] communicates if the count of servers in its row or column is greater than 1.

• Sum Communicating Servers: Sum the number of servers identified as communicating.

• Time Complexity: O(m*n), Space Complexity: O(m+n)

Code

    def countServers(grid):
    """
    Counts the number of servers that can communicate with each other in a grid.

    Args:
        grid: A list of lists of integers representing the server grid.

    Returns:
        The number of servers that can communicate with each other.
    """

    m = len(grid)
    n = len(grid[0])
    row_counts = [0] * m
    col_counts = [0] * n

    # Count servers in each row and column
    for i in range(m):
        for j in range(n):
            if grid[i][j] == 1:
                row_counts[i] += 1
                col_counts[j] += 1

    # Count communicating servers
    communicating_servers = 0
    for i in range(m):
        for j in range(n):
            if grid[i][j] == 1 and (row_counts[i] > 1 or col_counts[j] > 1):
                communicating_servers += 1

    return communicating_servers