# Solving Leetcode Interviews in Seconds with AI: Count Subarrays With Fixed Bounds


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "2444" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> You are given an integer array nums and two integers minK and maxK. A fixed-bound subarray of nums is a subarray that satisfies the following conditions:  The minimum value in the subarray is equal to minK. The maximum value in the subarray is equal to maxK.  Return the number of fixed-bound subarrays. A subarray is a contiguous part of an array.   Example 1:  Input: nums = [1,3,5,2,7,5], minK = 1, maxK = 5 Output: 2 Explanation: The fixed-bound subarrays are [1,3,5] and [1,3,5,2].  Example 2:  Input: nums = [1,1,1,1], minK = 1, maxK = 1 Output: 10 Explanation: Every subarray of nums is a fixed-bound subarray. There are 10 possible subarrays.    Constraints:  2 <= nums.length <= 105 1 <= nums[i], minK, maxK <= 106  

	# Explanation
	Here's a solution to the problem of finding the number of fixed-bound subarrays:

*   **Sliding Window Approach:** Use a sliding window to iterate through the array. The window expands until it contains both `minK` and `maxK`.
*   **Track Indices:** Keep track of the most recent indices of `minK` and `maxK` within the current window. Also, track the index of the most recent element outside the valid range (`minK` to `maxK`).
*   **Count Valid Subarrays:** When both `minK` and `maxK` are within the window, the number of valid subarrays ending at the current index is determined by the minimum of the indices of the most recent `minK` and `maxK` minus the index of the element outside the valid range.

*   **Time Complexity:** O(n), where n is the length of the input array.  **Space Complexity:** O(1).

	
	# Code
	```python
	def count_fixed_bound_subarrays(nums, minK, maxK):
    """
    Counts the number of fixed-bound subarrays in the given array.

    Args:
        nums: The input integer array.
        minK: The minimum value in the fixed-bound subarray.
        maxK: The maximum value in the fixed-bound subarray.

    Returns:
        The number of fixed-bound subarrays.
    """

    count = 0
    min_index = -1
    max_index = -1
    left_bound = -1  # Index of the most recent element outside the valid range

    for i, num in enumerate(nums):
        if num < minK or num > maxK:
            left_bound = i
        if num == minK:
            min_index = i
        if num == maxK:
            max_index = i

        if min_index != -1 and max_index != -1:
            start = max(min_index, max_index)
            count += max(0, start - left_bound)  # Ensure the count is non-negative

    return count
	```