Solving Leetcode Interviews in Seconds with AI: Count Total Number of Colored Cells
Introduction
In this blog post, we will explore how to solve the LeetCode problem "2579" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
There exists an infinitely large two-dimensional grid of uncolored unit cells. You are given a positive integer n, indicating that you must do the following routine for n minutes: At the first minute, color any arbitrary unit cell blue. Every minute thereafter, color blue every uncolored cell that touches a blue cell. Below is a pictorial representation of the state of the grid after minutes 1, 2, and 3. Return the number of colored cells at the end of n minutes. Example 1: Input: n = 1 Output: 1 Explanation: After 1 minute, there is only 1 blue cell, so we return 1. Example 2: Input: n = 2 Output: 5 Explanation: After 2 minutes, there are 4 colored cells on the boundary and 1 in the center, so we return 5. Constraints: 1 <= n <= 105
Explanation
Here's the breakdown of the solution:
- Pattern Recognition: The colored cells form a diamond shape that expands outwards each minute. The number of cells can be calculated directly based on the side length of the diamond.
- Formula Derivation: The number of colored cells after n minutes can be determined by the formula:
2*n*n - 2*n + 1which simplifies to(2 * n * n) - (2 * n) + 1. Direct Calculation: The code calculates the number of colored cells directly using the above formula.
Complexity: O(1) runtime, O(1) storage.
Code
def colored_cells(n: int) -> int:
"""
Calculates the number of colored cells after n minutes.
Args:
n: The number of minutes.
Returns:
The number of colored cells after n minutes.
"""
return (2 * n * n) - (2 * n) + 1