Introduction

In this blog post, we will explore how to solve the LeetCode problem "1108" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given a valid (IPv4) IP address, return a defanged version of that IP address. A defanged IP address replaces every period "." with "[.]". Example 1: Input: address = "1.1.1.1" Output: "1[.]1[.]1[.]1" Example 2: Input: address = "255.100.50.0" Output: "255[.]100[.]50[.]0" Constraints: The given address is a valid IPv4 address.

Explanation

Here's a solution to defang an IP address, focusing on efficiency:

• String Replacement: Directly replace all occurrences of the period (".") with "[.]" within the input string. This is the most straightforward and efficient approach for this specific task in Python.

• Built-in Function: Leverage Python's built-in replace() method, which is optimized for string manipulation.

• Time and Space Complexity: O(n) time complexity, where n is the length of the IP address string. O(n) space complexity because a new string (the defanged version) is created.

Code

    def defang_ip_address(address: str) -> str:
    """
    Given a valid (IPv4) IP address, return a defanged version of that IP address.
    A defanged IP address replaces every period "." with "[.]".

    Example:
    defang_ip_address("1.1.1.1") == "1[.]1[.]1[.]1"
    defang_ip_address("255.100.50.0") == "255[.]100[.]50[.]0"
    """
    return address.replace(".", "[.]")