# Solving Leetcode Interviews in Seconds with AI: Defanging an IP Address


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1108" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given a valid (IPv4) IP address, return a defanged version of that IP address. A defanged IP address replaces every period "." with "[.]".   Example 1: Input: address = "1.1.1.1"
 Output: "1[.]1[.]1[.]1"
 Example 2: Input: address = "255.100.50.0"
 Output: "255[.]100[.]50[.]0"
    Constraints:  The given address is a valid IPv4 address. 

	# Explanation
	Here's a solution to defang an IP address, focusing on efficiency:

*   **String Replacement:** Directly replace all occurrences of the period (".") with "[.]" within the input string. This is the most straightforward and efficient approach for this specific task in Python.
*   **Built-in Function:** Leverage Python's built-in `replace()` method, which is optimized for string manipulation.

*   **Time and Space Complexity:** O(n) time complexity, where n is the length of the IP address string. O(n) space complexity because a new string (the defanged version) is created.

	
	# Code
	```python
	def defang_ip_address(address: str) -> str:
    """
    Given a valid (IPv4) IP address, return a defanged version of that IP address.
    A defanged IP address replaces every period "." with "[.]".

    Example:
    defang_ip_address("1.1.1.1") == "1[.]1[.]1[.]1"
    defang_ip_address("255.100.50.0") == "255[.]100[.]50[.]0"
    """
    return address.replace(".", "[.]")
	```