Introduction

In this blog post, we will explore how to solve the LeetCode problem "1603" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Design a parking system for a parking lot. The parking lot has three kinds of parking spaces: big, medium, and small, with a fixed number of slots for each size. Implement the ParkingSystem class: ParkingSystem(int big, int medium, int small) Initializes object of the ParkingSystem class. The number of slots for each parking space are given as part of the constructor. bool addCar(int carType) Checks whether there is a parking space of carType for the car that wants to get into the parking lot. carType can be of three kinds: big, medium, or small, which are represented by 1, 2, and 3 respectively. A car can only park in a parking space of its carType. If there is no space available, return false, else park the car in that size space and return true. Example 1: Input ["ParkingSystem", "addCar", "addCar", "addCar", "addCar"] [[1, 1, 0], [1], [2], [3], [1]] Output [null, true, true, false, false] Explanation ParkingSystem parkingSystem = new ParkingSystem(1, 1, 0); parkingSystem.addCar(1); // return true because there is 1 available slot for a big car parkingSystem.addCar(2); // return true because there is 1 available slot for a medium car parkingSystem.addCar(3); // return false because there is no available slot for a small car parkingSystem.addCar(1); // return false because there is no available slot for a big car. It is already occupied. Constraints: 0 <= big, medium, small <= 1000 carType is 1, 2, or 3 At most 1000 calls will be made to addCar

Explanation

• Initialization: Store the initial number of slots for each car type (big, medium, small) in a dictionary or list.
  • Car Addition: When a car arrives, check if there's an available slot of the car's type. If so, decrement the corresponding slot count and return True. Otherwise, return False.

• Runtime Complexity: O(1) for addCar and initialization. Storage Complexity: O(1) as the space used is constant regardless of the input.

Code

    class ParkingSystem:

    def __init__(self, big: int, medium: int, small: int):
        self.slots = {
            1: big,
            2: medium,
            3: small
        }

    def addCar(self, carType: int) -> bool:
        if self.slots[carType] > 0:
            self.slots[carType] -= 1
            return True
        else:
            return False