Solving Leetcode Interviews in Seconds with AI: Determine if Two Events Have Conflict
Introduction
In this blog post, we will explore how to solve the LeetCode problem "2446" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
You are given two arrays of strings that represent two inclusive events that happened on the same day, event1 and event2, where: event1 = [startTime1, endTime1] and event2 = [startTime2, endTime2]. Event times are valid 24 hours format in the form of HH:MM. A conflict happens when two events have some non-empty intersection (i.e., some moment is common to both events). Return true if there is a conflict between two events. Otherwise, return false. Example 1: Input: event1 = ["01:15","02:00"], event2 = ["02:00","03:00"] Output: true Explanation: The two events intersect at time 2:00. Example 2: Input: event1 = ["01:00","02:00"], event2 = ["01:20","03:00"] Output: true Explanation: The two events intersect starting from 01:20 to 02:00. Example 3: Input: event1 = ["10:00","11:00"], event2 = ["14:00","15:00"] Output: false Explanation: The two events do not intersect. Constraints: event1.length == event2.length == 2 event1[i].length == event2[i].length == 5 startTime1 <= endTime1 startTime2 <= endTime2 All the event times follow the HH:MM format.
Explanation
- Convert to Minutes: Convert the start and end times of both events from HH:MM format to minutes since midnight. This simplifies the comparison of time intervals.
- Check for Overlap: Determine if the intervals overlap. Two intervals [start1, end1] and [start2, end2] overlap if and only if
start1 <= end2andstart2 <= end1. - Return Boolean: Return
Trueif there is an overlap (conflict), andFalseotherwise.
- Check for Overlap: Determine if the intervals overlap. Two intervals [start1, end1] and [start2, end2] overlap if and only if
- Time Complexity: O(1), Space Complexity: O(1)
Code
def haveConflict(event1, event2):
"""
Checks if two events have a conflict (overlap).
Args:
event1: A list of two strings representing the start and end time of the first event.
event2: A list of two strings representing the start and end time of the second event.
Returns:
True if the events have a conflict, False otherwise.
"""
def to_minutes(time):
hours, minutes = map(int, time.split(':'))
return hours * 60 + minutes
start1 = to_minutes(event1[0])
end1 = to_minutes(event1[1])
start2 = to_minutes(event2[0])
end2 = to_minutes(event2[1])
return start1 <= end2 and start2 <= end1