# Solving Leetcode Interviews in Seconds with AI: Determine if Two Events Have Conflict


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "2446" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> You are given two arrays of strings that represent two inclusive events that happened on the same day, event1 and event2, where:  event1 = [startTime1, endTime1] and event2 = [startTime2, endTime2].  Event times are valid 24 hours format in the form of HH:MM. A conflict happens when two events have some non-empty intersection (i.e., some moment is common to both events). Return true if there is a conflict between two events. Otherwise, return false.   Example 1:  Input: event1 = ["01:15","02:00"], event2 = ["02:00","03:00"] Output: true Explanation: The two events intersect at time 2:00.  Example 2:  Input: event1 = ["01:00","02:00"], event2 = ["01:20","03:00"] Output: true Explanation: The two events intersect starting from 01:20 to 02:00.  Example 3:  Input: event1 = ["10:00","11:00"], event2 = ["14:00","15:00"] Output: false Explanation: The two events do not intersect.    Constraints:  event1.length == event2.length == 2 event1[i].length == event2[i].length == 5 startTime1 <= endTime1 startTime2 <= endTime2 All the event times follow the HH:MM format.  

	# Explanation
	*   **Convert to Minutes:** Convert the start and end times of both events from HH:MM format to minutes since midnight. This simplifies the comparison of time intervals.
*   **Check for Overlap:** Determine if the intervals overlap. Two intervals [start1, end1] and [start2, end2] overlap if and only if `start1 <= end2` and `start2 <= end1`.
*   **Return Boolean:** Return `True` if there is an overlap (conflict), and `False` otherwise.

*   **Time Complexity:** O(1), **Space Complexity:** O(1)

	
	# Code
	```python
	def haveConflict(event1, event2):
    """
    Checks if two events have a conflict (overlap).

    Args:
        event1: A list of two strings representing the start and end time of the first event.
        event2: A list of two strings representing the start and end time of the second event.

    Returns:
        True if the events have a conflict, False otherwise.
    """

    def to_minutes(time):
        hours, minutes = map(int, time.split(':'))
        return hours * 60 + minutes

    start1 = to_minutes(event1[0])
    end1 = to_minutes(event1[1])
    start2 = to_minutes(event2[0])
    end2 = to_minutes(event2[1])

    return start1 <= end2 and start2 <= end1
	```