# Solving Leetcode Interviews in Seconds with AI: Difference Between Element Sum and Digit Sum of an Array


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "2535" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> You are given a positive integer array nums.  The element sum is the sum of all the elements in nums. The digit sum is the sum of all the digits (not necessarily distinct) that appear in nums.  Return the absolute difference between the element sum and digit sum of nums. Note that the absolute difference between two integers x and y is defined as |x - y|.   Example 1:  Input: nums = [1,15,6,3] Output: 9 Explanation:  The element sum of nums is 1 + 15 + 6 + 3 = 25. The digit sum of nums is 1 + 1 + 5 + 6 + 3 = 16. The absolute difference between the element sum and digit sum is |25 - 16| = 9.  Example 2:  Input: nums = [1,2,3,4] Output: 0 Explanation: The element sum of nums is 1 + 2 + 3 + 4 = 10. The digit sum of nums is 1 + 2 + 3 + 4 = 10. The absolute difference between the element sum and digit sum is |10 - 10| = 0.    Constraints:  1 <= nums.length <= 2000 1 <= nums[i] <= 2000  

	# Explanation
	*   Calculate the element sum of the input array `nums`.
*   Calculate the digit sum of the input array `nums`.
*   Return the absolute difference between the element sum and the digit sum.

*   Runtime Complexity: O(N * log(M)), where N is the number of elements in `nums` and M is the maximum value of an element in `nums`. Storage Complexity: O(1).

	
	# Code
	```python
	def differenceOfSum(nums: list[int]) -> int:
    """
    Given a positive integer array nums.
    The element sum is the sum of all the elements in nums.
    The digit sum is the sum of all the digits (not necessarily distinct) that appear in nums.
    Return the absolute difference between the element sum and digit sum of nums.
    Note that the absolute difference between two integers x and y is defined as |x - y|.

    For example:
    differenceOfSum([1,15,6,3]) == 9
    differenceOfSum([1,2,3,4]) == 0
    """

    element_sum = sum(nums)
    digit_sum = 0
    for num in nums:
        while num > 0:
            digit_sum += num % 10
            num //= 10
    return abs(element_sum - digit_sum)
	```