Solving Leetcode Interviews in Seconds with AI: Distribute Money to Maximum Children
Introduction
In this blog post, we will explore how to solve the LeetCode problem "2591" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
You are given an integer money denoting the amount of money (in dollars) that you have and another integer children denoting the number of children that you must distribute the money to. You have to distribute the money according to the following rules: All money must be distributed. Everyone must receive at least 1 dollar. Nobody receives 4 dollars. Return the maximum number of children who may receive exactly 8 dollars if you distribute the money according to the aforementioned rules. If there is no way to distribute the money, return -1. Example 1: Input: money = 20, children = 3 Output: 1 Explanation: The maximum number of children with 8 dollars will be 1. One of the ways to distribute the money is: - 8 dollars to the first child. - 9 dollars to the second child. - 3 dollars to the third child. It can be proven that no distribution exists such that number of children getting 8 dollars is greater than 1. Example 2: Input: money = 16, children = 2 Output: 2 Explanation: Each child can be given 8 dollars. Constraints: 1 <= money <= 200 2 <= children <= 30
Explanation
Here's a breakdown of the approach, followed by the Python code:
- Initial Allocation: First, ensure every child receives at least $1. This reduces both
moneyandchildrenby the number of children. - Maximize Eights: Greedily assign $7 to as many children as possible (so that they receive $1 + $7 = $8 in total).
Handle Remaining Money and Special Cases: After the greedy allocation, deal with the remaining money. Ensure no child ends up with exactly $4 and that all money is distributed.
Runtime Complexity: O(1) & Storage Complexity: O(1) - The solution involves a fixed number of arithmetic operations regardless of input size.
Code
def distributeMoney(money: int, children: int) -> int:
"""
Distributes money to children according to the given rules and returns the maximum number of children
who can receive exactly 8 dollars.
"""
if money < children:
return -1
money -= children
count = 0
if money // 7 >= children:
return children - 1 if money % 7 == 0 else children
count = money // 7
money %= 7
remaining_children = children - count
if remaining_children == 1 and money == 3:
count -= 1
return count