Introduction

In this blog post, we will explore how to solve the LeetCode problem "649" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

In the world of Dota2, there are two parties: the Radiant and the Dire. The Dota2 senate consists of senators coming from two parties. Now the Senate wants to decide on a change in the Dota2 game. The voting for this change is a round-based procedure. In each round, each senator can exercise one of the two rights: Ban one senator's right: A senator can make another senator lose all his rights in this and all the following rounds. Announce the victory: If this senator found the senators who still have rights to vote are all from the same party, he can announce the victory and decide on the change in the game. Given a string senate representing each senator's party belonging. The character 'R' and 'D' represent the Radiant party and the Dire party. Then if there are n senators, the size of the given string will be n. The round-based procedure starts from the first senator to the last senator in the given order. This procedure will last until the end of voting. All the senators who have lost their rights will be skipped during the procedure. Suppose every senator is smart enough and will play the best strategy for his own party. Predict which party will finally announce the victory and change the Dota2 game. The output should be "Radiant" or "Dire". Example 1: Input: senate = "RD" Output: "Radiant" Explanation: The first senator comes from Radiant and he can just ban the next senator's right in round 1. And the second senator can't exercise any rights anymore since his right has been banned. And in round 2, the first senator can just announce the victory since he is the only guy in the senate who can vote. Example 2: Input: senate = "RDD" Output: "Dire" Explanation: The first senator comes from Radiant and he can just ban the next senator's right in round 1. And the second senator can't exercise any rights anymore since his right has been banned. And the third senator comes from Dire and he can ban the first senator's right in round 1. And in round 2, the third senator can just announce the victory since he is the only guy in the senate who can vote. Constraints: n == senate.length 1 <= n <= 104 senate[i] is either 'R' or 'D'.

Explanation

Here's the solution to the Dota2 Senate problem:

• High-Level Approach: The core idea is to simulate the voting process round by round. Instead of actually removing senators, we use a queue to keep track of senators who still have voting rights. Each senator, when their turn comes, will try to ban a senator from the opposing party. If no opposing senator is available in the current round, the current senator's right is deferred to the next round. When a party has no more senators in the queue, the other party wins.

• Complexity: Time Complexity: O(N), where N is the number of senators. Space Complexity: O(N) due to the queues.

Code

    from collections import deque

def predictPartyVictory(senate: str) -> str:
    """
    Predicts which party will win the Dota2 senate voting.
    """
    radiant = deque()
    dire = deque()
    n = len(senate)

    for i, s in enumerate(senate):
        if s == 'R':
            radiant.append(i)
        else:
            dire.append(i)

    while radiant and dire:
        r_idx = radiant.popleft()
        d_idx = dire.popleft()

        if r_idx < d_idx:
            radiant.append(r_idx + n)
        else:
            dire.append(d_idx + n)

    if radiant:
        return "Radiant"
    else:
        return "Dire"