Solving Leetcode Interviews in Seconds with AI: Fibonacci Number
Introduction
In this blog post, we will explore how to solve the LeetCode problem "509" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
The Fibonacci numbers, commonly denoted F(n) form a sequence, called the Fibonacci sequence, such that each number is the sum of the two preceding ones, starting from 0 and 1. That is, F(0) = 0, F(1) = 1 F(n) = F(n - 1) + F(n - 2), for n > 1. Given n, calculate F(n). Example 1: Input: n = 2 Output: 1 Explanation: F(2) = F(1) + F(0) = 1 + 0 = 1. Example 2: Input: n = 3 Output: 2 Explanation: F(3) = F(2) + F(1) = 1 + 1 = 2. Example 3: Input: n = 4 Output: 3 Explanation: F(4) = F(3) + F(2) = 2 + 1 = 3. Constraints: 0 <= n <= 30
Explanation
- Iterative Approach: Calculate Fibonacci numbers iteratively using a loop, avoiding recursion to enhance efficiency.
- Constant Space: Store only the two most recent Fibonacci numbers, minimizing memory usage.
- Runtime Complexity: O(n), Storage Complexity: O(1)
Code
def fib(n: int) -> int:
"""
Calculate the nth Fibonacci number.
Args:
n: The index of the Fibonacci number to calculate.
Returns:
The nth Fibonacci number.
"""
if n <= 1:
return n
a = 0
b = 1
for _ in range(2, n + 1):
temp = a + b
a = b
b = temp
return b