# Solving Leetcode Interviews in Seconds with AI: Find Closest Number to Zero


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "2239" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given an integer array nums of size n, return the number with the value closest to 0 in nums. If there are multiple answers, return the number with the largest value.   Example 1:  Input: nums = [-4,-2,1,4,8] Output: 1 Explanation: The distance from -4 to 0 is |-4| = 4. The distance from -2 to 0 is |-2| = 2. The distance from 1 to 0 is |1| = 1. The distance from 4 to 0 is |4| = 4. The distance from 8 to 0 is |8| = 8. Thus, the closest number to 0 in the array is 1.  Example 2:  Input: nums = [2,-1,1] Output: 1 Explanation: 1 and -1 are both the closest numbers to 0, so 1 being larger is returned.    Constraints:  1 <= n <= 1000 -105 <= nums[i] <= 105  

	# Explanation
	Here's the breakdown:

*   **Initialization:** Initialize `closest_num` with the first element of the array.
*   **Iteration and Comparison:** Iterate through the rest of the array. In each step, compare the absolute difference between the current number and 0 with the absolute difference between `closest_num` and 0.
*   **Update:** If the current number is closer to 0, or if it's equally close but larger than `closest_num`, update `closest_num`.

*   **Runtime Complexity:** O(n), **Storage Complexity:** O(1)

	
	# Code
	```python
	def find_closest_number(nums):
    """
    Finds the number in the array closest to 0.
    If there are ties, returns the largest number.
    """

    closest_num = nums[0]

    for num in nums:
        if abs(num) < abs(closest_num):
            closest_num = num
        elif abs(num) == abs(closest_num) and num > closest_num:
            closest_num = num

    return closest_num
	```