Introduction

In this blog post, we will explore how to solve the LeetCode problem "3285" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

There are n mountains in a row, and each mountain has a height. You are given an integer array height where height[i] represents the height of mountain i, and an integer threshold. A mountain is called stable if the mountain just before it (if it exists) has a height strictly greater than threshold. Note that mountain 0 is not stable. Return an array containing the indices of all stable mountains in any order. Example 1: Input: height = [1,2,3,4,5], threshold = 2 Output: [3,4] Explanation: Mountain 3 is stable because height[2] == 3 is greater than threshold == 2. Mountain 4 is stable because height[3] == 4 is greater than threshold == 2. Example 2: Input: height = [10,1,10,1,10], threshold = 3 Output: [1,3] Example 3: Input: height = [10,1,10,1,10], threshold = 10 Output: [] Constraints: 2 <= n == height.length <= 100 1 <= height[i] <= 100 1 <= threshold <= 100

Explanation

Here's the solution to the problem:

• Iterate through the height array starting from the second mountain (index 1).
• For each mountain, check if the height of the previous mountain is strictly greater than the given threshold.

• If it is, add the current mountain's index to the result array.

• Runtime Complexity: O(n), where n is the number of mountains. Storage Complexity: O(k), where k is the number of stable mountains (in the worst case, O(n)).

Code

    def find_stable_mountains(height, threshold):
    """
    Finds the indices of stable mountains in an array of mountain heights.

    Args:
        height: An integer array representing the heights of the mountains.
        threshold: An integer representing the threshold height.

    Returns:
        An array containing the indices of all stable mountains in any order.
    """

    stable_mountains = []
    for i in range(1, len(height)):
        if height[i - 1] > threshold:
            stable_mountains.append(i)
    return stable_mountains