Introduction

In this blog post, we will explore how to solve the LeetCode problem "1295" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an array nums of integers, return how many of them contain an even number of digits. Example 1: Input: nums = [12,345,2,6,7896] Output: 2 Explanation: 12 contains 2 digits (even number of digits). 345 contains 3 digits (odd number of digits). 2 contains 1 digit (odd number of digits). 6 contains 1 digit (odd number of digits). 7896 contains 4 digits (even number of digits). Therefore only 12 and 7896 contain an even number of digits. Example 2: Input: nums = [555,901,482,1771] Output: 1 Explanation: Only 1771 contains an even number of digits. Constraints: 1 <= nums.length <= 500 1 <= nums[i] <= 105

Explanation

• Iterate and Count: Loop through each number in the input array. For each number, determine the number of digits it contains.
  • Digit Counting Optimization: Efficiently count the digits by converting the number to a string and checking its length.
  • Even Digit Check: Increment a counter if the number of digits is even.

• Runtime Complexity: O(n), where n is the number of elements in the input array. Storage Complexity: O(1).

Code

    def find_numbers(nums):
    """
    Given an array nums of integers, return how many of them contain an even number of digits.

    Args:
        nums (list[int]): A list of integers.

    Returns:
        int: The number of integers in nums that contain an even number of digits.
    """
    count = 0
    for num in nums:
        num_str = str(num)
        if len(num_str) % 2 == 0:
            count += 1
    return count