Introduction

In this blog post, we will explore how to solve the LeetCode problem "2917" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given an integer array nums, and an integer k. Let's introduce K-or operation by extending the standard bitwise OR. In K-or, a bit position in the result is set to 1 if at least k numbers in nums have a 1 in that position. Return the K-or of nums. Example 1: Input: nums = [7,12,9,8,9,15], k = 4 Output: 9 Explanation: Represent numbers in binary: Number Bit 3 Bit 2 Bit 1 Bit 0 7 0 1 1 1 12 1 1 0 0 9 1 0 0 1 8 1 0 0 0 9 1 0 0 1 15 1 1 1 1 Result = 9 1 0 0 1 Bit 0 is set in 7, 9, 9, and 15. Bit 3 is set in 12, 9, 8, 9, and 15. Only bits 0 and 3 qualify. The result is (1001)2 = 9. Example 2: Input: nums = [2,12,1,11,4,5], k = 6 Output: 0 Explanation: No bit appears as 1 in all six array numbers, as required for K-or with k = 6. Thus, the result is 0. Example 3: Input: nums = [10,8,5,9,11,6,8], k = 1 Output: 15 Explanation: Since k == 1, the 1-or of the array is equal to the bitwise OR of all its elements. Hence, the answer is 10 OR 8 OR 5 OR 9 OR 11 OR 6 OR 8 = 15. Constraints: 1 <= nums.length <= 50 0 <= nums[i] < 231 1 <= k <= nums.length

Explanation

• Bit Counting: Iterate through each bit position (0 to 30, as numbers are less than 2³¹). For each bit, count how many numbers in the input array have that bit set to 1.
  • K-or Condition: If the count for a particular bit position is greater than or equal to k, then set that bit in the result.
  • Result Accumulation: Construct the final result by combining the bits that satisfy the K-or condition.

• Time Complexity: O(N * log(max(nums))), where N is the length of nums. Space Complexity: O(1).

Code

    def k_or(nums, k):
    """
    Calculates the K-or of an array of integers.

    Args:
        nums: A list of integers.
        k: An integer representing the minimum number of elements required
           to have a '1' in a bit position for that bit to be set in the result.

    Returns:
        An integer representing the K-or of the input array.
    """
    result = 0
    for bit_position in range(31):  # Check bits from 0 to 30
        count = 0
        for num in nums:
            if (num >> bit_position) & 1:
                count += 1
        if count >= k:
            result |= (1 << bit_position)

    return result