Solving Leetcode Interviews in Seconds with AI: Find the Maximum Achievable Number
Introduction
In this blog post, we will explore how to solve the LeetCode problem "2769" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
Given two integers, num and t. A number x is achievable if it can become equal to num after applying the following operation at most t times: Increase or decrease x by 1, and simultaneously increase or decrease num by 1. Return the maximum possible value of x. Example 1: Input: num = 4, t = 1 Output: 6 Explanation: Apply the following operation once to make the maximum achievable number equal to num: Decrease the maximum achievable number by 1, and increase num by 1. Example 2: Input: num = 3, t = 2 Output: 7 Explanation: Apply the following operation twice to make the maximum achievable number equal to num: Decrease the maximum achievable number by 1, and increase num by 1. Constraints: 1 <= num, t <= 50
Explanation
Here's the solution:
- Understanding the Operation: Each operation effectively changes the difference between
xandnumby 2. The problem asks us to maximize x. - Maximizing x: To maximize
x, we want to perform 't' operations in a way such that we add to the initial value ofx. For each operation, consider decreasing x by 1 and increasing num by 1. Then the difference between num and x becomes larger, meaning after t operations, num is larger than x. So x will need to start with larger value and decrease by 1 while num increases by 1. The opposite will happen if x starts with small value and increases by 1 while num decreases by 1. Final Calculation: Since the difference changes by 2 with each operation, the maximum achievable value of
xwill benum + 2 * t.Runtime Complexity: O(1) & Storage Complexity: O(1)
Code
def get_max_achievable_number(num: int, t: int) -> int:
"""
Given two integers, num and t. A number x is achievable if it can become equal to num
after applying the following operation at most t times:
Increase or decrease x by 1, and simultaneously increase or decrease num by 1.
Return the maximum possible value of x.
Example 1:
Input: num = 4, t = 1
Output: 6
Explanation: Apply the following operation once to make the maximum achievable number equal to num:
Decrease the maximum achievable number by 1, and increase num by 1.
Example 2:
Input: num = 3, t = 2
Output: 7
Explanation: Apply the following operation twice to make the maximum achievable number equal to num:
Decrease the maximum achievable number by 1, and increase num by 1.
Constraints:
1 <= num, t <= 50
"""
return num + 2 * t