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Solving Leetcode Interviews in Seconds with AI: Find the Maximum Achievable Number

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3 min read

Introduction

In this blog post, we will explore how to solve the LeetCode problem "2769" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given two integers, num and t. A number x is achievable if it can become equal to num after applying the following operation at most t times: Increase or decrease x by 1, and simultaneously increase or decrease num by 1. Return the maximum possible value of x. Example 1: Input: num = 4, t = 1 Output: 6 Explanation: Apply the following operation once to make the maximum achievable number equal to num: Decrease the maximum achievable number by 1, and increase num by 1. Example 2: Input: num = 3, t = 2 Output: 7 Explanation: Apply the following operation twice to make the maximum achievable number equal to num: Decrease the maximum achievable number by 1, and increase num by 1. Constraints: 1 <= num, t <= 50

Explanation

Here's the solution:

  • Understanding the Operation: Each operation effectively changes the difference between x and num by 2. The problem asks us to maximize x.
  • Maximizing x: To maximize x, we want to perform 't' operations in a way such that we add to the initial value of x. For each operation, consider decreasing x by 1 and increasing num by 1. Then the difference between num and x becomes larger, meaning after t operations, num is larger than x. So x will need to start with larger value and decrease by 1 while num increases by 1. The opposite will happen if x starts with small value and increases by 1 while num decreases by 1.
  • Final Calculation: Since the difference changes by 2 with each operation, the maximum achievable value of x will be num + 2 * t.

  • Runtime Complexity: O(1) & Storage Complexity: O(1)

Code

    def get_max_achievable_number(num: int, t: int) -> int:
    """
    Given two integers, num and t. A number x is achievable if it can become equal to num
    after applying the following operation at most t times:
    Increase or decrease x by 1, and simultaneously increase or decrease num by 1.
    Return the maximum possible value of x.

    Example 1:
    Input: num = 4, t = 1
    Output: 6
    Explanation: Apply the following operation once to make the maximum achievable number equal to num:
    Decrease the maximum achievable number by 1, and increase num by 1.

    Example 2:
    Input: num = 3, t = 2
    Output: 7
    Explanation: Apply the following operation twice to make the maximum achievable number equal to num:
    Decrease the maximum achievable number by 1, and increase num by 1.

    Constraints:
    1 <= num, t <= 50
    """
    return num + 2 * t

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