Introduction

In this blog post, we will explore how to solve the LeetCode problem "3255" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given an array of integers nums of length n and a positive integer k. The power of an array is defined as: Its maximum element if all of its elements are consecutive and sorted in ascending order. -1 otherwise. You need to find the power of all subarrays of nums of size k. Return an integer array results of size n - k + 1, where results[i] is the power of nums[i..(i + k - 1)]. Example 1: Input: nums = [1,2,3,4,3,2,5], k = 3 Output: [3,4,-1,-1,-1] Explanation: There are 5 subarrays of nums of size 3: [1, 2, 3] with the maximum element 3. [2, 3, 4] with the maximum element 4. [3, 4, 3] whose elements are not consecutive. [4, 3, 2] whose elements are not sorted. [3, 2, 5] whose elements are not consecutive. Example 2: Input: nums = [2,2,2,2,2], k = 4 Output: [-1,-1] Example 3: Input: nums = [3,2,3,2,3,2], k = 2 Output: [-1,3,-1,3,-1] Constraints: 1 <= n == nums.length <= 105 1 <= nums[i] <= 106 1 <= k <= n

Explanation

Here's a breakdown of the solution:

• Sliding Window: Iterate through the array using a sliding window of size k.
• Consecutive Check: For each window, verify if the elements are consecutive and sorted in ascending order.

• Power Calculation: If the condition is met, the power is the maximum element of the window; otherwise, it's -1.

• Time Complexity: O(n k), *Space Complexity: O(n - k + 1)

Code

    def subarray_powers(nums, k):
    """
    Calculates the power of all subarrays of size k in the given array.

    Args:
        nums: A list of integers.
        k: The size of the subarray.

    Returns:
        A list of integers representing the power of each subarray.
    """
    n = len(nums)
    results = []
    for i in range(n - k + 1):
        subarray = nums[i:i + k]
        is_consecutive = True
        is_sorted = True

        for j in range(1, k):
            if subarray[j] != subarray[j - 1] + 1:
                is_consecutive = False
                break
            if subarray[j] < subarray[j-1]:
                is_sorted = False
                break

        if is_consecutive and is_sorted:
            results.append(subarray[-1])
        else:
            results.append(-1)

    return results