Introduction

In this blog post, we will explore how to solve the LeetCode problem "3079" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given an integer array nums containing positive integers. We define a function encrypt such that encrypt(x) replaces every digit in x with the largest digit in x. For example, encrypt(523) = 555 and encrypt(213) = 333. Return the sum of encrypted elements. Example 1: Input: nums = [1,2,3] Output: 6 Explanation: The encrypted elements are [1,2,3]. The sum of encrypted elements is 1 + 2 + 3 == 6. Example 2: Input: nums = [10,21,31] Output: 66 Explanation: The encrypted elements are [11,22,33]. The sum of encrypted elements is 11 + 22 + 33 == 66. Constraints: 1 <= nums.length <= 50 1 <= nums[i] <= 1000

Explanation

Here's an efficient solution to the problem:

• Encryption Logic: For each number, find the largest digit and replace all digits with it.

• Iterative Summation: Sum the encrypted numbers as you compute them, for efficiency.

• Runtime Complexity: O(N D), where N is the number of elements in nums, and D is the number of digits in each number (at most 4 in our case due to constraints). *Storage Complexity: O(1).

Code

    def sum_of_encrypted_elements(nums):
    """
    Calculates the sum of encrypted elements in the given array.

    Args:
        nums: A list of positive integers.

    Returns:
        The sum of the encrypted elements.
    """
    total_sum = 0
    for num in nums:
        num_str = str(num)
        max_digit = '0'
        for digit in num_str:
            if digit > max_digit:
                max_digit = digit

        encrypted_num_str = max_digit * len(num_str)
        encrypted_num = int(encrypted_num_str)
        total_sum += encrypted_num

    return total_sum