# Solving Leetcode Interviews in Seconds with AI: Find the Sum of Encrypted Integers


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "3079" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> You are given an integer array nums containing positive integers. We define a function encrypt such that encrypt(x) replaces every digit in x with the largest digit in x. For example, encrypt(523) = 555 and encrypt(213) = 333. Return the sum of encrypted elements.   Example 1:  Input: nums = [1,2,3] Output: 6 Explanation: The encrypted elements are [1,2,3]. The sum of encrypted elements is 1 + 2 + 3 == 6.  Example 2:  Input: nums = [10,21,31] Output: 66 Explanation: The encrypted elements are [11,22,33]. The sum of encrypted elements is 11 + 22 + 33 == 66.    Constraints:  1 <= nums.length <= 50 1 <= nums[i] <= 1000  

	# Explanation
	Here's an efficient solution to the problem:

*   **Encryption Logic:** For each number, find the largest digit and replace all digits with it.
*   **Iterative Summation:** Sum the encrypted numbers as you compute them, for efficiency.

*   **Runtime Complexity:** O(N * D), where N is the number of elements in `nums`, and D is the number of digits in each number (at most 4 in our case due to constraints).
    **Storage Complexity:** O(1).

	
	# Code
	```python
	def sum_of_encrypted_elements(nums):
    """
    Calculates the sum of encrypted elements in the given array.

    Args:
        nums: A list of positive integers.

    Returns:
        The sum of the encrypted elements.
    """
    total_sum = 0
    for num in nums:
        num_str = str(num)
        max_digit = '0'
        for digit in num_str:
            if digit > max_digit:
                max_digit = digit

        encrypted_num_str = max_digit * len(num_str)
        encrypted_num = int(encrypted_num_str)
        total_sum += encrypted_num

    return total_sum
	```