Introduction

In this blog post, we will explore how to solve the LeetCode problem "2639" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given a 0-indexed m x n integer matrix grid. The width of a column is the maximum length of its integers. For example, if grid = [[-10], [3], [12]], the width of the only column is 3 since -10 is of length 3. Return an integer array ans of size n where ans[i] is the width of the ith column. The length of an integer x with len digits is equal to len if x is non-negative, and len + 1 otherwise. Example 1: Input: grid = [[1],[22],[333]] Output: [3] Explanation: In the 0th column, 333 is of length 3. Example 2: Input: grid = [[-15,1,3],[15,7,12],[5,6,-2]] Output: [3,1,2] Explanation: In the 0th column, only -15 is of length 3. In the 1st column, all integers are of length 1. In the 2nd column, both 12 and -2 are of length 2. Constraints: m == grid.length n == grid[i].length 1 <= m, n <= 100 -109 <= grid[r][c] <= 109

Explanation

• Iterate through columns: The solution iterates through each column of the input matrix grid.
  • Calculate max width: For each column, the solution computes the maximum width required to represent all integers in that column. The width of an integer is determined by the number of digits it contains, plus one if the integer is negative.
  • Store and return: The computed maximum widths for each column are stored in a result array, which is then returned.

• Time Complexity: O(m*n), where m is the number of rows and n is the number of columns in the grid. Space Complexity: O(n), to store the result array.

Code

    def findColumnWidth(grid: list[list[int]]) -> list[int]:
    m = len(grid)
    n = len(grid[0])
    ans = [0] * n

    for j in range(n):
        max_width = 0
        for i in range(m):
            num = grid[i][j]
            width = len(str(abs(num))) + (1 if num < 0 else 0)
            max_width = max(max_width, width)
        ans[j] = max_width

    return ans