Introduction

In this blog post, we will explore how to solve the LeetCode problem "3222" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given two positive integers x and y, denoting the number of coins with values 75 and 10 respectively. Alice and Bob are playing a game. Each turn, starting with Alice, the player must pick up coins with a total value 115. If the player is unable to do so, they lose the game. Return the name of the player who wins the game if both players play optimally. Example 1: Input: x = 2, y = 7 Output: "Alice" Explanation: The game ends in a single turn: Alice picks 1 coin with a value of 75 and 4 coins with a value of 10. Example 2: Input: x = 4, y = 11 Output: "Bob" Explanation: The game ends in 2 turns: Alice picks 1 coin with a value of 75 and 4 coins with a value of 10. Bob picks 1 coin with a value of 75 and 4 coins with a value of 10. Constraints: 1 <= x, y <= 100

Explanation

Here's the breakdown of the approach and the Python code:

• Game State Analysis: The core idea is to determine the conditions under which a player cannot make a move. A player loses if they can't pick coins summing to 115.
• Winning Condition: The game's outcome depends entirely on how many turns can be played. We calculate how many turns are possible given x (number of 75-value coins) and y (number of 10-value coins). Each turn requires one 75-value coin and four 10-value coins.

• Turn Calculation: The number of turns possible is limited by either the number of 75-value coins or the number of sets of four 10-value coins. The min(x, y // 4) determines the number of possible turns.

• Runtime Complexity: O(1) & Storage Complexity: O(1)

Code

    def solve():
    x, y = map(int, input().split())

    turns = min(x, y // 4)

    if turns % 2 == 1:
        print("Alice")
    else:
        print("Bob")

solve()