# Solving Leetcode Interviews in Seconds with AI: Hamming Distance


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "461" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> The Hamming distance between two integers is the number of positions at which the corresponding bits are different. Given two integers x and y, return the Hamming distance between them.   Example 1:  Input: x = 1, y = 4 Output: 2 Explanation: 1   (0 0 0 1) 4   (0 1 0 0)        ↑   ↑ The above arrows point to positions where the corresponding bits are different.  Example 2:  Input: x = 3, y = 1 Output: 1    Constraints:  0 <= x, y <= 231 - 1    Note: This question is the same as  2220: Minimum Bit Flips to Convert Number. 

	# Explanation
	*   **XOR Operation:** Use the XOR (exclusive OR) operation on the two integers. The XOR operation results in a number where each bit is 1 if the corresponding bits in the input integers are different, and 0 if they are the same.
*   **Bit Counting:** Count the number of set bits (1s) in the result of the XOR operation. This count represents the Hamming distance. We can efficiently count set bits using bitwise operations.

*   **Time Complexity:** O(1), **Space Complexity:** O(1)

	
	# Code
	```python
	def hammingDistance(x: int, y: int) -> int:
    """
    Calculates the Hamming distance between two integers.

    Args:
        x: The first integer.
        y: The second integer.

    Returns:
        The Hamming distance between x and y.
    """
    xor_result = x ^ y
    distance = 0
    while xor_result > 0:
        distance += xor_result & 1
        xor_result >>= 1
    return distance
	```