# Solving Leetcode Interviews in Seconds with AI: Height Checker


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1051" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> A school is trying to take an annual photo of all the students. The students are asked to stand in a single file line in non-decreasing order by height. Let this ordering be represented by the integer array expected where expected[i] is the expected height of the ith student in line. You are given an integer array heights representing the current order that the students are standing in. Each heights[i] is the height of the ith student in line (0-indexed). Return the number of indices where heights[i] != expected[i].   Example 1:  Input: heights = [1,1,4,2,1,3] Output: 3 Explanation:  heights:  [1,1,4,2,1,3] expected: [1,1,1,2,3,4] Indices 2, 4, and 5 do not match.  Example 2:  Input: heights = [5,1,2,3,4] Output: 5 Explanation: heights:  [5,1,2,3,4] expected: [1,2,3,4,5] All indices do not match.  Example 3:  Input: heights = [1,2,3,4,5] Output: 0 Explanation: heights:  [1,2,3,4,5] expected: [1,2,3,4,5] All indices match.    Constraints:  1 <= heights.length <= 100 1 <= heights[i] <= 100  

	# Explanation
	Here's an efficient solution to the problem:

*   **Sorting:** Create a sorted copy of the input `heights` array. This sorted array represents the `expected` arrangement.
*   **Comparison:** Iterate through both the original `heights` and the sorted `expected` arrays, comparing elements at each index.
*   **Counting Mismatches:** Increment a counter each time the elements at the same index in the two arrays are different.

*   **Runtime Complexity:** O(n log n), where n is the number of students (due to sorting). **Storage Complexity:** O(n),  for storing the sorted copy of the array.

	
	# Code
	```python
	def heightChecker(heights):
    """
    Calculates the number of indices where heights[i] != expected[i].

    Args:
        heights: A list of integers representing the current order of student heights.

    Returns:
        The number of mismatched indices.
    """
    expected = sorted(heights)
    mismatched_count = 0
    for i in range(len(heights)):
        if heights[i] != expected[i]:
            mismatched_count += 1
    return mismatched_count
	```