Introduction

In this blog post, we will explore how to solve the LeetCode problem "55" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given an integer array nums. You are initially positioned at the array's first index, and each element in the array represents your maximum jump length at that position. Return true if you can reach the last index, or false otherwise. Example 1: Input: nums = [2,3,1,1,4] Output: true Explanation: Jump 1 step from index 0 to 1, then 3 steps to the last index. Example 2: Input: nums = [3,2,1,0,4] Output: false Explanation: You will always arrive at index 3 no matter what. Its maximum jump length is 0, which makes it impossible to reach the last index. Constraints: 1 <= nums.length <= 104 0 <= nums[i] <= 105

Explanation

Here's the breakdown of the solution:

• Greedy Approach: Iterate through the array, keeping track of the farthest index reachable so far.
• Update Reachable Index: At each position, update the farthest reachable index by taking the maximum of the current farthest reach and the current position plus the jump length at that position.

• Check for Dead End: If at any point the current position is beyond the farthest reachable index, it means we cannot reach the current position, and thus cannot reach the end.

• Runtime Complexity: O(n), Storage Complexity: O(1)

Code

    def canJump(nums):
    """
    Determines if it's possible to reach the last index of an array given jump lengths.

    Args:
        nums: An integer array where each element represents the maximum jump length at that position.

    Returns:
        True if it's possible to reach the last index, False otherwise.
    """
    reachable = 0
    for i, jump in enumerate(nums):
        if i > reachable:
            return False
        reachable = max(reachable, i + jump)
    return True