# Solving Leetcode Interviews in Seconds with AI: K Items With the Maximum Sum


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "2600" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> There is a bag that consists of items, each item has a number 1, 0, or -1 written on it. You are given four non-negative integers numOnes, numZeros, numNegOnes, and k. The bag initially contains:  numOnes items with 1s written on them. numZeroes items with 0s written on them. numNegOnes items with -1s written on them.  We want to pick exactly k items among the available items. Return the maximum possible sum of numbers written on the items.   Example 1:  Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 2 Output: 2 Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 2 items with 1 written on them and get a sum in a total of 2. It can be proven that 2 is the maximum possible sum.  Example 2:  Input: numOnes = 3, numZeros = 2, numNegOnes = 0, k = 4 Output: 3 Explanation: We have a bag of items with numbers written on them {1, 1, 1, 0, 0}. We take 3 items with 1 written on them, and 1 item with 0 written on it, and get a sum in a total of 3. It can be proven that 3 is the maximum possible sum.    Constraints:  0 <= numOnes, numZeros, numNegOnes <= 50 0 <= k <= numOnes + numZeros + numNegOnes  

	# Explanation
	Here's an efficient solution to the problem:

*   **Prioritize Ones:** Greedily take as many ones as possible, up to `k`.
*   **Consider Zeros:** If we haven't reached `k` yet, take zeros. Zeros don't affect the sum, but they allow us to reach `k`.
*   **Use Negative Ones if Needed:** If we *still* haven't reached `k` after taking all ones and zeros, we have to take negative ones, which will reduce the sum.

*   **Runtime Complexity:** O(1), **Storage Complexity:** O(1)

	
	# Code
	```python
	def kItemsWithMaximumSum(numOnes: int, numZeros: int, numNegOnes: int, k: int) -> int:
    """
    Calculates the maximum possible sum of numbers written on items picked from the bag.
    """

    if k <= numOnes:
        return k
    elif k <= numOnes + numZeros:
        return numOnes
    else:
        return numOnes - (k - numOnes - numZeros)
	```