Introduction

In this blog post, we will explore how to solve the LeetCode problem "1431" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

There are n kids with candies. You are given an integer array candies, where each candies[i] represents the number of candies the ith kid has, and an integer extraCandies, denoting the number of extra candies that you have. Return a boolean array result of length n, where result[i] is true if, after giving the ith kid all the extraCandies, they will have the greatest number of candies among all the kids, or false otherwise. Note that multiple kids can have the greatest number of candies. Example 1: Input: candies = [2,3,5,1,3], extraCandies = 3 Output: [true,true,true,false,true] Explanation: If you give all extraCandies to: - Kid 1, they will have 2 + 3 = 5 candies, which is the greatest among the kids. - Kid 2, they will have 3 + 3 = 6 candies, which is the greatest among the kids. - Kid 3, they will have 5 + 3 = 8 candies, which is the greatest among the kids. - Kid 4, they will have 1 + 3 = 4 candies, which is not the greatest among the kids. - Kid 5, they will have 3 + 3 = 6 candies, which is the greatest among the kids. Example 2: Input: candies = [4,2,1,1,2], extraCandies = 1 Output: [true,false,false,false,false] Explanation: There is only 1 extra candy. Kid 1 will always have the greatest number of candies, even if a different kid is given the extra candy. Example 3: Input: candies = [12,1,12], extraCandies = 10 Output: [true,false,true] Constraints: n == candies.length 2 <= n <= 100 1 <= candies[i] <= 100 1 <= extraCandies <= 50

Explanation

Here's the solution:

• Find the maximum number of candies among all kids.
• For each kid, check if adding extraCandies to their current candies results in a number greater than or equal to the maximum.

• Store the boolean result for each kid in a list.

• Runtime Complexity: O(n), where n is the number of kids. Storage Complexity: O(n) for the result array.

Code

    def kidsWithCandies(candies: list[int], extraCandies: int) -> list[bool]:
    """
    Given an integer array candies, where each candies[i] represents the number of candies the ith kid has, and an integer extraCandies,
    denoting the number of extra candies that you have. Return a boolean array result of length n, where result[i] is true if, after giving
    the ith kid all the extraCandies, they will have the greatest number of candies among all the kids, or false otherwise.
    Note that multiple kids can have the greatest number of candies.
    """
    max_candies = max(candies)
    result = []
    for candy_count in candies:
        result.append(candy_count + extraCandies >= max_candies)
    return result