# Solving Leetcode Interviews in Seconds with AI: Largest Merge Of Two Strings


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1754" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> You are given two strings word1 and word2. You want to construct a string merge in the following way: while either word1 or word2 are non-empty, choose one of the following options:  If word1 is non-empty, append the first character in word1 to merge and delete it from word1.  	 For example, if word1 = "abc" and merge = "dv", then after choosing this operation, word1 = "bc" and merge = "dva".   If word2 is non-empty, append the first character in word2 to merge and delete it from word2. 	 For example, if word2 = "abc" and merge = "", then after choosing this operation, word2 = "bc" and merge = "a".    Return the lexicographically largest merge you can construct. A string a is lexicographically larger than a string b (of the same length) if in the first position where a and b differ, a has a character strictly larger than the corresponding character in b. For example, "abcd" is lexicographically larger than "abcc" because the first position they differ is at the fourth character, and d is greater than c.   Example 1:  Input: word1 = "cabaa", word2 = "bcaaa" Output: "cbcabaaaaa" Explanation: One way to get the lexicographically largest merge is: - Take from word1: merge = "c", word1 = "abaa", word2 = "bcaaa" - Take from word2: merge = "cb", word1 = "abaa", word2 = "caaa" - Take from word2: merge = "cbc", word1 = "abaa", word2 = "aaa" - Take from word1: merge = "cbca", word1 = "baa", word2 = "aaa" - Take from word1: merge = "cbcab", word1 = "aa", word2 = "aaa" - Append the remaining 5 a's from word1 and word2 at the end of merge.  Example 2:  Input: word1 = "abcabc", word2 = "abdcaba" Output: "abdcabcabcaba"    Constraints:  1 <= word1.length, word2.length <= 3000 word1 and word2 consist only of lowercase English letters.  

	# Explanation
	Here's a breakdown of the approach, followed by the Python code:

*   **Greedy Approach:** At each step, choose the string (word1 or word2) that will lead to the lexicographically larger merge. This involves comparing the suffixes of both strings starting from their current first characters.
*   **Suffix Comparison:** When the first characters of the remaining parts of `word1` and `word2` are the same, compare the suffixes of `word1` and `word2` to determine which string to pick from. If the suffixes are equal, prioritize picking from `word1` (as per the problem requirement when there is a tie).
*   **Build the Merge:** Append the chosen character to the `merge` string and remove it from the corresponding word. Repeat until both words are empty.

*   **Time Complexity:** O(m*n), where m and n are the lengths of word1 and word2 respectively (due to suffix comparison). **Space Complexity:** O(m+n) to store the resulting merged string.

	
	# Code
	```python
	def largestMerge(word1: str, word2: str) -> str:
    """
    Constructs the lexicographically largest merge of two strings.
    """
    merge = ""
    i = 0
    j = 0
    while i < len(word1) and j < len(word2):
        if word1[i:] > word2[j:]:
            merge += word1[i]
            i += 1
        else:
            merge += word2[j]
            j += 1

    merge += word1[i:]
    merge += word2[j:]
    return merge
	```