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Solving Leetcode Interviews in Seconds with AI: Largest Palindrome Product

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2 min read

Introduction

In this blog post, we will explore how to solve the LeetCode problem "479" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given an integer n, return the largest palindromic integer that can be represented as the product of two n-digits integers. Since the answer can be very large, return it modulo 1337. Example 1: Input: n = 2 Output: 987 Explanation: 99 x 91 = 9009, 9009 % 1337 = 987 Example 2: Input: n = 1 Output: 9 Constraints: 1 <= n <= 8

Explanation

Here's a solution to find the largest palindromic integer that can be represented as the product of two n-digit integers, modulo 1337.

  • High-level approach: Construct palindromes in descending order and check if each palindrome can be factored into the product of two n-digit numbers. Start with the largest possible n-digit numbers to efficiently find the largest palindromic product. The key is to build the palindrome from the first half, then check divisibility.

  • Complexity: Time Complexity: O(10n), Storage Complexity: O(1)

Code

    def largestPalindromeProduct(n: int) -> int:
    """
    Finds the largest palindromic integer that can be represented as the
    product of two n-digit integers, modulo 1337.

    Args:
        n: The number of digits.

    Returns:
        The largest palindromic product modulo 1337.
    """

    if n == 1:
        return 9

    upper_bound = 10**n - 1
    lower_bound = 10**(n - 1)

    for i in range(upper_bound, lower_bound -1, -1):
        palindrome = int(str(i) + str(i)[::-1])

        for j in range(upper_bound, int(palindrome**0.5) -1, -1):
            if palindrome % j == 0:
                other_factor = palindrome // j
                if (lower_bound <= other_factor <= upper_bound):
                    return palindrome % 1337

    return 0 # Should not reach here given the constraints.

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