Solving Leetcode Interviews in Seconds with AI: Lemonade Change
Introduction
In this blog post, we will explore how to solve the LeetCode problem "860" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
At a lemonade stand, each lemonade costs $5. Customers are standing in a queue to buy from you and order one at a time (in the order specified by bills). Each customer will only buy one lemonade and pay with either a $5, $10, or $20 bill. You must provide the correct change to each customer so that the net transaction is that the customer pays $5. Note that you do not have any change in hand at first. Given an integer array bills where bills[i] is the bill the ith customer pays, return true if you can provide every customer with the correct change, or false otherwise. Example 1: Input: bills = [5,5,5,10,20] Output: true Explanation: From the first 3 customers, we collect three $5 bills in order. From the fourth customer, we collect a $10 bill and give back a $5. From the fifth customer, we give a $10 bill and a $5 bill. Since all customers got correct change, we output true. Example 2: Input: bills = [5,5,10,10,20] Output: false Explanation: From the first two customers in order, we collect two $5 bills. For the next two customers in order, we collect a $10 bill and give back a $5 bill. For the last customer, we can not give the change of $15 back because we only have two $10 bills. Since not every customer received the correct change, the answer is false. Constraints: 1 <= bills.length <= 105 bills[i] is either 5, 10, or 20.
Explanation
Here's the breakdown of the approach, complexity, and the Python code:
High-Level Approach:
- Maintain a count of $5 and $10 bills we have.
- Iterate through the
billsarray. For each bill, check if we can provide the correct change. If not, returnFalse. - If we successfully provide change to all customers, return
True.
Complexity:
- Runtime Complexity: O(n), where n is the number of customers (length of
bills). - Storage Complexity: O(1), as we only store the counts of $5 and $10 bills.
- Runtime Complexity: O(n), where n is the number of customers (length of
Code
def lemonadeChange(bills):
"""
Determines if you can provide the correct change to every customer at a lemonade stand.
Args:
bills (list of int): An array where bills[i] is the bill the ith customer pays.
Returns:
bool: True if you can provide change to every customer, False otherwise.
"""
five_dollar_bills = 0
ten_dollar_bills = 0
for bill in bills:
if bill == 5:
five_dollar_bills += 1
elif bill == 10:
if five_dollar_bills > 0:
five_dollar_bills -= 1
ten_dollar_bills += 1
else:
return False
else: # bill == 20
if ten_dollar_bills > 0 and five_dollar_bills > 0:
ten_dollar_bills -= 1
five_dollar_bills -= 1
elif five_dollar_bills >= 3:
five_dollar_bills -= 3
else:
return False
return True