Solving Leetcode Interviews in Seconds with AI: Maximum and Minimum Sums of at Most Size K Subarrays
Introduction
In this blog post, we will explore how to solve the LeetCode problem "3430" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.
Problem Statement
You are given an integer array nums and a positive integer k. Return the sum of the maximum and minimum elements of all subarrays with at most k elements. Example 1: Input: nums = [1,2,3], k = 2 Output: 20 Explanation: The subarrays of nums with at most 2 elements are: Subarray Minimum Maximum Sum [1] 1 1 2 [2] 2 2 4 [3] 3 3 6 [1, 2] 1 2 3 [2, 3] 2 3 5 Final Total 20 The output would be 20. Example 2: Input: nums = [1,-3,1], k = 2 Output: -6 Explanation: The subarrays of nums with at most 2 elements are: Subarray Minimum Maximum Sum [1] 1 1 2 [-3] -3 -3 -6 [1] 1 1 2 [1, -3] -3 1 -2 [-3, 1] -3 1 -2 Final Total -6 The output would be -6. Constraints: 1 <= nums.length <= 80000 1 <= k <= nums.length -106 <= nums[i] <= 106
Explanation
Here's the solution:
- Iterate through all possible subarrays of
numswith length at mostk. - For each subarray, find the minimum and maximum elements.
Add the sum of the minimum and maximum to the running total.
Time Complexity: O(n*k), Space Complexity: O(1)
Code
def sub_array_max_min(nums, k):
"""
Calculates the sum of the maximum and minimum elements of all subarrays with at most k elements.
Args:
nums (list[int]): An integer array.
k (int): A positive integer representing the maximum length of subarrays.
Returns:
int: The sum of the maximum and minimum elements of all subarrays with at most k elements.
"""
total_sum = 0
n = len(nums)
for i in range(n):
for j in range(i, min(i + k, n)):
sub_array = nums[i : j+1]
min_val = min(sub_array)
max_val = max(sub_array)
total_sum += min_val + max_val
return total_sum