Introduction

In this blog post, we will explore how to solve the LeetCode problem "2779" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

You are given a 0-indexed array nums and a non-negative integer k. In one operation, you can do the following: Choose an index i that hasn't been chosen before from the range [0, nums.length - 1]. Replace nums[i] with any integer from the range [nums[i] - k, nums[i] + k]. The beauty of the array is the length of the longest subsequence consisting of equal elements. Return the maximum possible beauty of the array nums after applying the operation any number of times. Note that you can apply the operation to each index only once. A subsequence of an array is a new array generated from the original array by deleting some elements (possibly none) without changing the order of the remaining elements. Example 1: Input: nums = [4,6,1,2], k = 2 Output: 3 Explanation: In this example, we apply the following operations: - Choose index 1, replace it with 4 (from range [4,8]), nums = [4,4,1,2]. - Choose index 3, replace it with 4 (from range [0,4]), nums = [4,4,1,4]. After the applied operations, the beauty of the array nums is 3 (subsequence consisting of indices 0, 1, and 3). It can be proven that 3 is the maximum possible length we can achieve. Example 2: Input: nums = [1,1,1,1], k = 10 Output: 4 Explanation: In this example we don't have to apply any operations. The beauty of the array nums is 4 (whole array). Constraints: 1 <= nums.length <= 105 0 <= nums[i], k <= 105

Explanation

Here's the breakdown:

• Core Idea: Iterate through all possible target values (the values we want to make our equal-element subsequence). For each target, count how many numbers in the input array can be transformed into that target value using the given operation.
• Range Check: For a number to be transformable into the target, the target must lie within the range [num - k, num + k].

• Optimization: Since the input range is bounded (0 to 10^5), we can iterate through all possible target values within this range.

• Complexity: Time: O(N + M), where N is the length of nums and M is the range of possible values (0 to 10^5). Space: O(1).

Code

    def maxBeauty(nums, k):
    """
    Calculates the maximum possible beauty of the array after applying the operation any number of times.

    Args:
        nums: A 0-indexed array of integers.
        k: A non-negative integer.

    Returns:
        The maximum possible beauty of the array.
    """

    max_beauty = 0
    for target in range(201):  # Iterate through possible target values (0 to 200)
        count = 0
        for num in nums:
            if target >= num - k and target <= num + k:
                count += 1
        max_beauty = max(max_beauty, count)

    return max_beauty