# Solving Leetcode Interviews in Seconds with AI: Maximum Difference Between Adjacent Elements in a Circular Array


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "3423" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given a circular array nums, find the maximum absolute difference between adjacent elements. Note: In a circular array, the first and last elements are adjacent.   Example 1:  Input: nums = [1,2,4] Output: 3 Explanation: Because nums is circular, nums[0] and nums[2] are adjacent. They have the maximum absolute difference of |4 - 1| = 3.  Example 2:  Input: nums = [-5,-10,-5] Output: 5 Explanation: The adjacent elements nums[0] and nums[1] have the maximum absolute difference of |-5 - (-10)| = 5.    Constraints:  2 <= nums.length <= 100 -100 <= nums[i] <= 100  

	# Explanation
	Here's the breakdown of the approach, complexity, and the Python code:

*   **Approach:**
    *   Iterate through the array, calculating the absolute difference between adjacent elements.
    *   Consider the circular nature of the array by calculating the absolute difference between the first and last elements.
    *   Maintain and update a variable to store the maximum absolute difference found so far.

*   **Complexity:**
    *   Runtime Complexity: O(n)
    *   Storage Complexity: O(1)

	
	# Code
	```python
	def max_absolute_difference(nums):
    """
    Finds the maximum absolute difference between adjacent elements in a circular array.

    Args:
        nums: A list of integers representing the circular array.

    Returns:
        The maximum absolute difference between adjacent elements.
    """

    max_diff = 0
    n = len(nums)

    for i in range(n - 1):
        max_diff = max(max_diff, abs(nums[i] - nums[i+1]))

    max_diff = max(max_diff, abs(nums[0] - nums[n-1]))

    return max_diff
	```