Introduction

In this blog post, we will explore how to solve the LeetCode problem "1614" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like Chatmagic, we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

Problem Statement

Given a valid parentheses string s, return the nesting depth of s. The nesting depth is the maximum number of nested parentheses. Example 1: Input: s = "(1+(23)+((8)/4))+1" Output: 3 Explanation: Digit 8 is inside of 3 nested parentheses in the string. Example 2: Input: s = "(1)+((2))+(((3)))" Output: 3 Explanation: Digit 3 is inside of 3 nested parentheses in the string. Example 3: Input: s = "()(())((()()))" Output: 3 Constraints: 1 <= s.length <= 100 s consists of digits 0-9 and characters '+', '-', '', '/', '(', and ')'. It is guaranteed that parentheses expression s is a VPS.

Explanation

Here's the approach to solve this problem:

• Iterate and Track: Iterate through the string character by character.
• Maintain Depth: Keep track of the current nesting depth by incrementing a counter when encountering an opening parenthesis '(' and decrementing when encountering a closing parenthesis ')'.

• Maximize Depth: Keep track of the maximum depth encountered so far.

• Runtime Complexity: O(n), where n is the length of the string. Storage Complexity: O(1).

Code

    def max_depth(s: str) -> int:
    """
    Given a valid parentheses string s, return the nesting depth of s.
    """
    max_depth = 0
    current_depth = 0
    for char in s:
        if char == '(':
            current_depth += 1
            max_depth = max(max_depth, current_depth)
        elif char == ')':
            current_depth -= 1
    return max_depth