# Solving Leetcode Interviews in Seconds with AI: Maximum Nesting Depth of the Parentheses


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1614" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> Given a valid parentheses string s, return the nesting depth of s. The nesting depth is the maximum number of nested parentheses.   Example 1:  Input: s = "(1+(2*3)+((8)/4))+1" Output: 3 Explanation: Digit 8 is inside of 3 nested parentheses in the string.  Example 2:  Input: s = "(1)+((2))+(((3)))" Output: 3 Explanation: Digit 3 is inside of 3 nested parentheses in the string.  Example 3:  Input: s = "()(())((()()))" Output: 3    Constraints:  1 <= s.length <= 100 s consists of digits 0-9 and characters '+', '-', '*', '/', '(', and ')'. It is guaranteed that parentheses expression s is a VPS.  

	# Explanation
	Here's the approach to solve this problem:

*   **Iterate and Track:** Iterate through the string character by character.
*   **Maintain Depth:** Keep track of the current nesting depth by incrementing a counter when encountering an opening parenthesis '(' and decrementing when encountering a closing parenthesis ')'.
*   **Maximize Depth:** Keep track of the maximum depth encountered so far.

*   **Runtime Complexity:** O(n), where n is the length of the string. **Storage Complexity:** O(1).

	
	# Code
	```python
	def max_depth(s: str) -> int:
    """
    Given a valid parentheses string s, return the nesting depth of s.
    """
    max_depth = 0
    current_depth = 0
    for char in s:
        if char == '(':
            current_depth += 1
            max_depth = max(max_depth, current_depth)
        elif char == ')':
            current_depth -= 1
    return max_depth
	```