# Solving Leetcode Interviews in Seconds with AI: Maximum Product Difference Between Two Pairs


	# Introduction
	In this blog post, we will explore how to solve the LeetCode problem "1913" using AI. LeetCode is a popular platform for preparing for coding interviews, and with the help of AI tools like [Chatmagic](https://www.chatmagic.app), we can generate solutions quickly and efficiently - helping you pass the interviews and get the job offer without having to study for months.

	# Problem Statement
	> The product difference between two pairs (a, b) and (c, d) is defined as (a * b) - (c * d).  For example, the product difference between (5, 6) and (2, 7) is (5 * 6) - (2 * 7) = 16.  Given an integer array nums, choose four distinct indices w, x, y, and z such that the product difference between pairs (nums[w], nums[x]) and (nums[y], nums[z]) is maximized. Return the maximum such product difference.   Example 1: 
 Input: nums = [5,6,2,7,4]
 Output: 34
 Explanation: We can choose indices 1 and 3 for the first pair (6, 7) and indices 2 and 4 for the second pair (2, 4).
 The product difference is (6 * 7) - (2 * 4) = 34.
  Example 2: 
 Input: nums = [4,2,5,9,7,4,8]
 Output: 64
 Explanation: We can choose indices 3 and 6 for the first pair (9, 8) and indices 1 and 5 for the second pair (2, 4).
 The product difference is (9 * 8) - (2 * 4) = 64.
    Constraints:  4 <= nums.length <= 104 1 <= nums[i] <= 104 

	# Explanation
	Here's a breakdown of the solution:

*   **Maximize the first product, minimize the second:** The goal is to maximize `(a * b) - (c * d)`. This is best achieved by selecting the two largest numbers from `nums` for `a` and `b`, and selecting the two smallest numbers from `nums` for `c` and `d`.
*   **Efficient Selection:** We can find the two largest and two smallest numbers efficiently without fully sorting the array.
*   **Calculate and Return:** Multiply the two largest and the two smallest, then subtract them to get the maximum product difference.

*   **Time & Space Complexity:** O(n) runtime, O(1) storage.

	
	# Code
	```python
	def maxProductDifference(nums):
    """
    Finds the maximum product difference between two pairs in the given array.

    Args:
    nums (list[int]): An integer array.

    Returns:
    int: The maximum product difference.
    """

    max1 = 0
    max2 = 0
    min1 = float('inf')
    min2 = float('inf')

    for num in nums:
        if num > max1:
            max2 = max1
            max1 = num
        elif num > max2:
            max2 = num

        if num < min1:
            min2 = min1
            min1 = num
        elif num < min2:
            min2 = num

    return (max1 * max2) - (min1 * min2)
	```